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0.75x^2+1.5x=4
We move all terms to the left:
0.75x^2+1.5x-(4)=0
a = 0.75; b = 1.5; c = -4;
Δ = b2-4ac
Δ = 1.52-4·0.75·(-4)
Δ = 14.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{14.25}}{2*0.75}=\frac{-1.5-\sqrt{14.25}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{14.25}}{2*0.75}=\frac{-1.5+\sqrt{14.25}}{1.5} $
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